In an ap s5+s7 167

WebJan 24, 2024 · Step-by-step explanation: Answer We know that sum of n terms sn = n/2 (2a + (n - 1) * d) Given s5 + s7 = 167. = 5/2 (2a + (5 - 1) * d) + 7/2 (2a + (7 - 1) d) = 167 = 5/2 (2a + 4d) + 7/2 (2a + 6d) = 167 = 5 (a + 2d) + 7 (a + 3d) = 167 = 5a + 10d + 7a + 21d = 167 = 12a + 31d = 167 ---------- (1) Given that s10 = 235 10/2 (2a + (10 - 1) * d) = 235 WebIn an A.P., if S5 + S7 = 167 and S 10= 235, then find the A.P., where Sn denotes the sum of its first n terms. Advertisement Remove all ads Solution S S and S S 5 + S 7 = 167 and S 10 = …

In an AP, S5 + S7 = 167 and S10 = 235, then find the AP, where Sn ...

WebSep 2, 2024 · S5+S7=5/2 (2a+4d)+7/2 (2a+6d) where a is the first term and d is the common ratio =S5+S7=5a+10d+7a+21d=167 similarly S10=10a+45d=235 on solving the two equations simultaneously we get a=1 and d=5 Hii hlo Find Math textbook solutions? Class 12 Class 11 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions … WebJul 9, 2024 · closed Jul 10, 2024 by Anaswara In an AP. It is given that S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. arithmetic progression class-10 1 Answer +2 votes answered Jul 9, 2024 by Dheeya (31.0k points) selected Jul 10, 2024 by Anaswara Best answer chinese luxury sedan https://aplustron.com

In an AP if S5+S7 =167 and S10 =235 then find S6. Class 10 cbse AP …

WebIn an AP, it is given that S 5 + S 7 = 167 a n d S 10 = 235, then find the AP, where S n denotes the sum of its first n terms. Q. In an AP, if S 5 + S 7 = 167 and S 10 = 235 , then find the … WebIn an AP, S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms urgently need this answer!!!! - Maths - Arithmetic Progressions WebIn an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, Where S n denotes the sum of its first n terms. 4564 Views Switch Flag Bookmark Advertisement The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7 : 15. Find the numbers. Answer grandparents stock photos

In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find …

Category:In an AP if S5 + S7 = 167 and S10 = 235. Then find the AP, …

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In an ap s5+s7 167

In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the

WebOct 15, 2024 · S5+S7=167 therefore 2a+10d=167 and a+9d=235 from these 2 equations we get d=12.625 therefore the ap starts with 40.75 and continue s with a difference d=12.625 olf they have given sum of terms not nth term, so the formula you're using is wrong...……... Find Math textbook solutions? See all Class Class 12 Class Class 11 Class Class 10 Class … WebAug 20, 2024 · In an AP, it is given that \( S_{5}+S_{7}=167 \) and \( S_{10}=235 \), then find the AP, where \( S_{n} \) denotes the sum of its first \( n \) terms.W📲PW A... In an AP, it is …

In an ap s5+s7 167

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WebFeb 13, 2016 · In an AP, if S5 + S7 = 167 and S10 = 235, then find the A P , where Sn denotes the sum of its first n term - Maths - Arithmetic Progressions. NCERT Solutions; Board Paper Solutions; ... 2 by 6, we get 12 a + 54 d = 282 .... 3 Subtracting 1 from 3, we get 54 d - 31 d = 282-167 ⇒ 23 d = 115 ⇒ d = ...

WebNov 30, 2024 · In an AP, if S5 +S7 =167 and S10 =235, then find the AP, where Sn denotes the sum of its first n terms. [2015] ...[2M] Corporate Off. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebIt is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. Arithmetic Progression CBSE Class 10 Maths RS Aggarwal. In an AP. …

WebFeb 1, 2024 · In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. asked Sep 14, 2024 in Mathematics by Mubarak (32.9k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to ... WebIn an AP, if S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. Solution: Question 25. The fourth term of an A.P. is 11. The sum of the fifth and seventh terms of the A.P. is 34. Find its common difference Solution: Question 26.

WebIn an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms Arithmetic Progression CBSE Class 10 Maths RS Aggarwal In an AP.

WebApr 12, 2024 · In an AP, If S5 + S7 = 167 and S10 = 235 then find the AP, where Sn - YouTube In this video i solved important questions of class 10 maths for term 2,the question is as followingIn an AP,... grandparents storeWebJun 19, 2024 · The sum of first 5 terms of an ap and the sum of first 7 terms of an ap is 167 if sum of first 10 terms of the ap is 235 find the sum of its first 20 terms Advertisement pradu4321 is waiting for your help. … chinese lying down exerciseWeb>> In an A.P., S5 + S7 = 167 and S10 = 2. ... Verified by Toppr. Was this answer helpful? 0. 0. Similar questions. If the 3rd and the 9th terms of an AP are 4 and -8 respectively. which term of this AP IS ZERO ? Medium. View solution > If the sum of 7 terms of an A.P is 4 9 and that of 1 7 terms is 2 8 9, find the sum of n terms. chinese lyciumWebIn an A.P., S5 + S7 = 167 and S10 = 235, then find the A.P., where Sn denotes the sum of first n terms. Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic … grandparents story tellingWebIn an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, where S n denotes the sum of its first n terms. chinese lynchburg tnWebThe sum of the sum of first five terms of an AP and the sum of the first seven terms of the same AP is 167. ... Consider an A.P. whose first term and the common difference are a and d respectively. According to the question: S5 + S7 = 167 (Given) \Rightarrow \frac{5}{2}[2 a+(5-1) d]+\frac{7}{2}[2 a+(7-1) d]=167\\ \Rightarrow 5\{2 a+4 d\}+7\{2 ... grandparents storytimeWebJan 2, 2024 · thesarcasticsoul Answer: S5+S7=5/2(2a+4d) +7/2(2a+6d)=167 =5a+10d+7a+21d=167 =12a+31d=167 [let this be eqn 1] similarly, from S10=235, we get 2a+9d=47 {let this be equation 2} by solving eqn 1 and 2, we get a=1 and d=5 therefore the ap is 1,6,11........ Step-by-step explanation: Advertisement Advertisement New questions in … chinese lyminge