Web2 days ago · Approach: The idea is to use recursion.Below are the steps: Create a recursive function gcd(str1, str2).; If the length of str2 is more than str1 then we will recur with gcd(str2, str1).; Now if str1 doesn’t start with str2 then return an empty string.; If the longer string begins with a shorter string, cut off the common prefix part of the longer string … WebHackerrank interview question for string divisiblilty. currentRepeat = currentRepeat + sequence.slice (currentRepeat.length, currentRepeat.length+1);

[LeetCode] Find the Divisibility Array of a String SUMFIのBlog

WebJan 1, 2024 · Given two strings s & t, determine if s is divisible by t. For example: "abab" is divisible by "ab" But "ababab" is not divisible by "abab". If it isn't divisible, return -1. If it is, return the length of the smallest common divisor: So, for "abababab" and "abab", return 2 as s is divisible by t and the smallest common divisor is "ab" with ... WebDec 6, 2024 · A string t "divides" a string s if len (s) is a multiple of len (t) and s == t * (len (s)//len (t)). As for finding the length of the smallest divisor of t, the classic trick for that is … lshw bus info

Number of subsequences in a string divisible by n

WebThe string "bcd" is the smallest string that can be concatenated to create both strings s and t. The length of the string u is 3, the integer value to return. Example 2: s = … WebApr 11, 2024 · See other coding analysis videos at our channel @Code-Yao Webclass Solution: def divisibilityArray(self, word: str, m: int) -> List[int]: def word2int(string): return int(string) def div(num,m): return 1 if num % m == 0 else 0 rest = [0 for i in … lshw centos